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Chapter 15: Q.10 - Excercises And Problems (page 415)

An object in simple harmonic motion has an amplitude of 8.0cm, a frequency of 0.25Hz, and a phase constant of -蟺/2rad. Draw a position graph showing two cycles of the motion.

Short Answer

Expert verified

The position graph as follows

Step by step solution

01

Given information

amplitude a=8.0cm

frequency f=0.25Hz

phase constant 胃=-蟺2rad

number of waves=2

02

Explanation

The wave equation is in the form

x=acos蝇t+胃

The angular frequency is in the form

蝇=2蟺蹿==2蟺(0.25)=0.5蟺rad/s

The equation now takes the form of substituting the values of angular frequency and phase constant.

x=(8.0cm)cos0.5蟺t-蟺2


Therefore the position graph shows two cycles of motion are as follows.

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