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A block oscillating on a spring has period T=2s. What is the period if:

a. The block's mass is doubled?Explain. Note that you do not know the value of either mor k, so do not assume any particular values for them. The required analysis involves thinking about ratios.

b. The value of the spring constant is quadrupled?

c. The oscillation amplitude is doubled while and kare unchanged?

Short Answer

Expert verified

a.The period is 2.828swhen block's mass is doubled.

b.The time if the spring constant is quadrupled is 1s.

c.The oscillation amplitude is double whilemandkchange time period.

Step by step solution

01

Formula for time

Use the following Formula to find the time.

T=2Ï€mk

Here, mis the mass and kis the spring constant.

02

Calculation of time (part a)

The initial time

T=2πmk⋯⋯·(1)

If the block mass is blocked, then m=2mand new time T'

T'=2Ï€2mk

T'=22Ï€mk

From equation (1)the above equation will be,

T'=2T

Substitute 2sfor Tin the above equation

T'=2(2s)

T'=2.828s

03

Calculation for time if the spring constant is quadrupled (part b)

b)

If the value of spring constant is quadrupled, then new time T'is,

T'=2Ï€m4k

T'=122Ï€mk

T'=12T

Substitute 2sfor Tin the above equation.

T'=12(2s)

T'=1s

04

Oscillation amplitude changes (part c)

c) Time doesn't depend on oscillation amplitude, until and unless m and k change time period.

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