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Chapter 15: Q. 4 (page 415)

An object in SHM oscillates with a period of 4.0sand an amplitude of 10cm. How long does the object take to move from x=0.0cm to x=6.0cm?

Short Answer

Expert verified

To move from x=0.0cmto x=6.0cm, the total time taken is 0.4s.

Step by step solution

01

Given Information 

Time period, T=4s.

The amplitude,A=10cm.

02

:Formula used 

Equation of the simple harmonic motion is x=Asin蝇t.

Where, at time t, xis the position, Ais the amplitude and蝇is the angular frequency.

03

Calculation 

Substitute the values to obtaint.

6=10sin2蟺T脳t610=sin2蟺4脳tsin-10.6=蟺2脳tt=0.4s
04

Final Answer 

To move from x=0.0cmto x=6.0cm, the total time taken is 0.4s.

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