/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 30 In FIGURE P35.30,  what are the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In FIGURE P35.30, what are the position, height, and orientation of the final image? Give the position as a distance to the right or left of the lens.

Short Answer

Expert verified

The position, height, and orientation of the final image is given below.

Step by step solution

01

Given information.

We need to find out the position, height, orient-tion, and a distance from right or left lens.

02

Simplify

As we can get the values from the diagram:

f1=10cmf2=-30cmh=1cmS1=5cm

Here, S1is the distance from lens, f1is the focal length of lens, his the height of the object,f2is the focal length of the mirror and S'1 is the distance of the image from the lens.

First, Let us find theS1'

s1'=f1S1S1-f1S1'=(10)(5)5-10S1'=50-5S1'=-10cm

03

Calculation.

Now, Let us find out S2'

S2'=f2S2S2-f2S2'=(-30)(15)15-(-30)S2'=-45045S2'=-10cm

Finally, Let us find S3', Sincef1=f3=10cm

S3'=f3S3S3-f3S3'=(10)(15)15-10S3'=1505S3'=30cm

Finally, we geth'from next relation:

h'=hS1'S1S2'S2S3'S3h'=(1.0cm)-10cm5.0cm-10cm15cm30cm15cmh'=2.7cm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 15cm-focal-length converging lens is 20cmto the right of a 7.0cm-focal-length converging lens. A 1.0cm-tall object is distance L to the left of the first lens.

a. For what value of L is the final image of this two-lens system halfway between the two lenses?

b. What are the height and orientation of the final image?

Ellen wears eyeglasses with the prescription-1.0D.

a. What eye condition does Ellen have?

b. What is her far point without the glasses?

Your task in physics laboratory is to make a microscope from two lenses. One lens has a focal length of 2.0 cm, the other 1.0 cm. You plan to use the more powerful lens as the objective, and you want the eyepiece to be 16 cm from the objective.

a. For viewing with a relaxed eye, how far should the sample be from the objective lens?

b. What is the magnification of your microscope?

A magnifier has a magnification of 5x. How far from the lens should an object be held so that its image is seen at the near-point distance of 25cm? Assume that your is immediately behind the lens.

Once dark adapted, the pupil of your eye is approximately 7 mm in diameter. The headlights of an oncoming car are 120 cm apart. If the lens of your eye is diffraction limited, at what distance are the two headlights marginally resolved? Assume a wavelength of 600 nm and that the index of refraction inside the eye is 1.33. (Your eye is not really good enough to resolve headlights at this distance, due both to aberrations in the lens and to the size of the receptors in your retina, but it comes reasonably close.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.