/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 30 a.  Derive an expression for λ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

a. Derive an expression for λ2→1, the wavelength of light emitted by a particle in a rigid box during a quantum jump from n=2ton=1.

b. In what length rigid box will an electron undergoing a 2→1 transition emit light with a wavelength of 694nm? This is the wavelength of a ruby laser

Short Answer

Expert verified

a. λ=8mcL23h

b.E=1.7867eV

Step by step solution

01

Part (a) Step 1: Given information

We have given,

n=2to1

we have to find the wavelength.

02

Simplify

We know that,

E=h28mL2(n22-n12)E=3h28mL2E=hcλλ=8mcL23h

03

Part (b) Step 1: Given information

We have given,

wavelength =694nm

we have to find the energy.

04

Simplify

E=hcλE=1240eV.nm694nmE=1.7867eV

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.