/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 3 Exercise Calculate the nuclear diameters ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Chapter 42: Q 3 Exercise (page 1236)

Calculate the nuclear diameters of(a)He4,(b)Fe56, and(c)U238.

Short Answer

Expert verified

Therefore, the nuclear radius and diameters are:

a.)r=1.904fm,d=3.8097fmb.)r=4.59103fm,d=9.18206fmc.)r=7.43658fm,d=14.87317fm

Step by step solution

01

Given information

ro=1.2fm

For radius we have,

r=roA1/3

For diameter we have,

d=2·r

02

Explanation

(a)The radius and diameter of the nucleus of 4He must be determined:

The radius is:

r=roA1/3r=(1.2fm)(4)1/3r=(1.2fm)(1.587)r=1.904fm

The diameter is:

d=2·rd=2·1.904fmd=3.8097fm

(b)The radius and diameter of the nucleus of Fe56must be determined:

The radius is:

r=roA1/3r=(1.2fm)(56)1/3r=(1.2fm)(3.82586)r=4.59103fm

The diameter is:

d=2rd=2×4.59103fmd=9.18206fm

03

Explanation

(c)The radius and diameter of the nucleus of U238must be determined:

The radius is:

r=roA1/3r=(1.2fm)(238)1/3r=(1.2fm)(6.19715)r=7.43658fm

The diameter is:

d=2rd=2×7.43658fmd=14.87317fm

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.