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91Ó°ÊÓ

FIGURECP7.57shows a200ghamster sitting on an 800gwedge-shaped block. The block, in turn, rests on a spring scale. An extra-fine lubricating oil having μs=μk=0is sprayed on the top surface of the block, causing the hamster to slide down. Friction between the block and the scale is large enough that the block does not slip on the scale. What does the scale read, in grams, as the hamster slides down?

Short Answer

Expert verified

The hamster slides down in scale is about920g

Step by step solution

01

Given information

mass of hamster m=200g

mass of the block M=800g

Angle of wedge blockθ=400

02

Explanation

The hamster accelerates down the block with a=gcosθ

The vertical component of this acceleration is: ay=gcos2(θ)

So the downward force exerted by the hamster on the block and thus onto the scale is

Fh=may

The net force exerted by the hamster on the block and thus onto the scale is

F=Mg+mgcos2(θ)⇒F=0.8×9.8+0.2×9.8×cos2(40)⇒F=9.0N

Therefore, the net force in gram can be calculated as

F=msg=9.0Nms=99.8×1000=920g

Therefore, the hamster slides down in scale about920g

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