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Mass of car $m_1=1000\mathrm{kg}$, mass of truck $m_2=2000\mathrm{kg}$, applied force $F=4500\mathrm{N}.$

The force of $4500N$is applied on the total mass (mass of car + mass of truck), with acceleration is given by :

$$\begin{gathered} F=ma \\ a=F/\left(m_1+m_2\right) \\ a=4500\mathrm{N}/(1000kg+2000kg) \\ a=4500N/3000kg \\ a=1.5\mathrm{m}/{\mathrm{s}}^2 \end{gathered}$$

From this, acceleration of truck and acceleration of car is same.

Now we have to find the force of the car on the truck . It will be equal to product of mass of truck and acceleration,

$$\begin{gathered} F=ma \\ F=2000kg脳1.5m/s^2 \\ F=3000\mathrm{N} \end{gathered}$$

The magnitude of force of the car on truck is $3000\mathrm{N}.$

The magnitude of the force of the car on the truck$3000N.$

Mass of car $m_1=1000kg$, mass of truck $m_2=2000kg$, applied force role="math" localid="1649449411813" $F=4500N.$

By Newton's 3rd Law, the force of the truck on the car must be equal but opposite to the force of the car on the truck.

The force of the truck is $-3000\mathrm{N}$and is applied in opposite direction to that of the force of the car.

The magnitude of force of the truck on car is $3000\mathrm{N}.$

The magnitude of the force of the truck on the car is$3000N.$