/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 37 The 10.2 kg block in FIGURE P7.... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The 10.2kg block in FIGURE P7.37is held in place by a force applied to a rope passing over two massless, frictionless pulleys. Find the tensions T1toT5and the magnitude of force F→.

Short Answer

Expert verified

Tension in the rope,T1=100N,T2=T3=T5=F=50NandT4=150N.

Step by step solution

01

Given information

Mass of the block, m=10.2kg

Given the mass and pulleys system

02

Explanation

Consider the equilibrium block

T1=mg

localid="1649647716658" T1=10.2kg×9.81m/s2=100N

Consider the equilibrium of a small pulley

T1=T2+T3

Since T2 and T3 are attached to the same pulley, therefore the tension T2=T3

localid="1649647731493" 100N=2T2T2=T3=50N

Similarly, T2 and T5 are attached to the same pulley, therefore the tension T2=T5

T5=50N

Since the tension in the ropeT5would be equal to the forceF

F=T5=50N

Consider the equilibrium of a large pulley

localid="1649647749005" T4=T2+T3+T5T4=50N+50N+50N=150N

Tension in the rope,T1=100N,T2=T3=T5=F=50NandT4=150N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A house painter uses the chair-and-pulley arrangement of FIGURE P7.45to lift himself up the side of a house. The painter’s mass is 70kgand the chair’s mass is 10kg. With what force must he pull down on the rope in order to accelerate upward at 0.20m/s2?

While driving to work last year, I was holding my coffee mug in my left hand while changing the CD with my right hand. Then the cell phone rang, so I placed the mug on the flat part of my dashboard. Then, believe it or not, a deer ran out of the woods and on to the road right in front of me. Fortunately, my reaction time was zero, and I was able to stop from a speed of 20m/s in a mere 50m, just barely avoiding the deer. Later tests revealed that the static and kinetic coefficients of friction of the coffee mug on the dash are 0.50 and 0.30, respectively; the coffee and mug had a mass of 0.50kg; and the mass of the deer was 120kg. Did my coffee mug slide?

You find yourself in the middle of a frozen lake with a surface so slippery μs=μk=0 you cannot walk. However, you happen to have several rocks in your pocket. The ice is extremely hard. It cannot be chipped, and the rocks slip on it just as much as your feet do. Can you think of a way to get to shore?Use pictures, forces, and Newton's laws to explain your reasoning.

A 40cmdiameter, 50cmtall, 15kghollow cylinder is placed on top of a 40cm-diameter, 30cm-tall, 100kgcylinder of solid aluminum, then the two are sent sliding across frictionless ice. The static and kinetic coefficients of friction between the cylinders are 0.45and 0.25, respectively. Air resistance cannot be neglected. What is the maximum speed the cylinders can have without the top cylinder sliding off?

Two packages at UPS start sliding down the20°ramp shown in FIGURE P7.33. Package A has a mass of5.0kg and a coefficient of friction of 0.20. Package B has a mass of 10kg and a coefficient of friction of0.15. How long does it take package A to reach the bottom?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.