/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 37 The 10.2聽kg block in FIGURE P7.... [FREE SOLUTION] | 91影视

91影视

The 10.2kg block in FIGURE P7.37is held in place by a force applied to a rope passing over two massless, frictionless pulleys. Find the tensions T1toT5and the magnitude of force F.

Short Answer

Expert verified

Tension in the rope,T1=100N,T2=T3=T5=F=50NandT4=150N.

Step by step solution

01

Given information

Mass of the block, m=10.2kg

Given the mass and pulleys system

02

Explanation

Consider the equilibrium block

T1=mg

localid="1649647716658" T1=10.2kg9.81m/s2=100N

Consider the equilibrium of a small pulley

T1=T2+T3

Since T2 and T3 are attached to the same pulley, therefore the tension T2=T3

localid="1649647731493" 100N=2T2T2=T3=50N

Similarly, T2 and T5 are attached to the same pulley, therefore the tension T2=T5

T5=50N

Since the tension in the ropeT5would be equal to the forceF

F=T5=50N

Consider the equilibrium of a large pulley

localid="1649647749005" T4=T2+T3+T5T4=50N+50N+50N=150N

Tension in the rope,T1=100N,T2=T3=T5=F=50NandT4=150N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

FIGUREP7.39shows a block of mass m resting on a 20slope. The block has coefficients of frictions=0.80 andk=0.50 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.0kg.

a. What is the minimum mass m that will stick and not slip?

b. If this minimum mass is nudged ever so slightly, it will start being pulled up the incline. What acceleration will it have?

Will hanging a magnet in front of the iron cart in the given figure make it go? Explain.

How does a sprinter sprint? What is the forward force on a sprinter as she accelerates? Where does that force come from? Your explanation should include an interaction diagram and a free-body diagram.

While driving to work last year, I was holding my coffee mug in my left hand while changing the CD with my right hand. Then the cell phone rang, so I placed the mug on the flat part of my dashboard. Then, believe it or not, a deer ran out of the woods and on to the road right in front of me. Fortunately, my reaction time was zero, and I was able to stop from a speed of 20m/s in a mere 50m, just barely avoiding the deer. Later tests revealed that the static and kinetic coefficients of friction of the coffee mug on the dash are 0.50 and 0.30, respectively; the coffee and mug had a mass of 0.50kg; and the mass of the deer was 120kg. Did my coffee mug slide?

A weightlifter stands up at constant speed from a squatting position while holding a heavy barbell across his shoulders.

a. Draw an interaction diagram.

b. Identify the 鈥渟ystem鈥 on your interaction diagram.

c. Draw a free-body diagram for each object in the system. Use

dashed lines to connect members of an action/reaction pair.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.