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The free-fall acceleration at the surface of planet 1 is 20 m/s2. The radius and the mass of planet 2 are twice those of planet 1. What is g on planet 2?

Short Answer

Expert verified

The value of g on planet 2 is : 10 m/s2

Step by step solution

01

Given Information

The free-fall acceleration at the surface of planet 1 is 20 m/s2

The radius and the mass of planet 2 are twice those of planet 1

02

Explanation

The free fall acceleration is calculated as below

g=GMr2

g= acceleration due to gravity,

M =mass

G = universal gravitational constant

r= distance from the center of mass of body

role="math" localid="1649255660263" g'g=Gmr2R2GMg'=g(2M)(2R)2R2Mg'=g2

Substitute the value

g'=20m/s22=10m/s2

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Most popular questions from this chapter

Let鈥檚 look in more detail at how a satellite is moved from one circular orbit to another. FIGURE CP13.71shows two circular orbits, of radii localid="1651418485730" r1and localid="1651418489556" r2, and an elliptical orbit that connects them. Points 1and 2are at the ends of the semimajor axis of the ellipse.

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