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A starship is circling a distant planet of radius R. The astronauts find that the free-fall acceleration at their altitude is half the value at the planet’s surface. How far above the surface are they orbiting? Your answer will be a multiple of R.

Short Answer

Expert verified

The starship is orbiting above 0.414Rabove the surface.

Step by step solution

01

Step 1. Given Information.

Acceleration on the surface of a planet = 2 times of the acceleration at a distance from the surface of a planet----1

02

Step 1. Apply the formula.

Acceleration on the surface of a planet with radius R=GMR2----i

Acceleration at a distance hfrom the surface of a planet with radius R=GMR+h2----ii

03

Step 3. Substitute the formulas.Substitute the equation i and ii into 1 and obtain, GMR2=2·GMR+h2.Then solve the obtained equation.

Substitute the equation iand iiinto 1and obtain, GMR2=2·GMR+h2.

Then solve the obtained equation.

2R2=R+h2R+hR=21+hR=2hR=2-1hR=1.414-1h=0.414R
04

Step 4. Final Answer.

The starship is orbiting 0.414Rabove the surface.

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