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A Ferris wheel of radius R speeds up with angular acceleration αstarting from rest. Find an expression for the (a) velocity and (b) centripetal acceleration of a rider after the Ferris wheel has rotated through angle∆θ.

Short Answer

Expert verified

a. The velocity of a rider after the Ferris wheel has rotated through angle ∆θisv=2α∆θR.

b. The centripetal acceleration of a rider after the Ferris wheel has rotated through angle∆θisa=2α∆θ¸é.

Step by step solution

01

Given information

A Ferris wheel of radius Rspeeds up with angular acceleration α starting from rest. We have to find an expression for the (a) velocity and (b) centripetal acceleration of a rider after the Ferris wheel has rotated through angle ∆θ.

02

Part a) Step 1: Calculation

The formula is:

Ӭf2=Ӭi2+2α∆θ

Where,

ӬfisfinalangularvelocityӬiisinitalangularvelocityαisangularaccelerationθisangle

By putting values in formula:

Ӭf2=0+2α∆θӬf=2α∆θv=Ӭf×Rv=2α∆θR

03

Part b) Step 1: Calculation

For centripetal acceleration:

Ӭf2=Ӭi2+2α∆θ

Where,

ӬfisfinalangularvelocityӬiisinitalangularvelocityαisangularaccelerationθisangle

Putting values in formula:

Ó¬f2=0+2α∆θӬf=2α∆θa=Ó¬f2×Ra=(2α∆θ)2Ra=2α∆θ¸é

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