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A long string is wrapped around a 6.0cmdiameter cylinder, initially at rest, that is free to rotate on an axle. The string is then pulled with a constant acceleration of 1.5m/s2 until 1.0m of string has been unwound. If the string unwinds without slipping, what is the cylinder’s angular speed, in rpm, at this time?

Short Answer

Expert verified

Ó¬=550rpm

Step by step solution

01

Step 1. Given Information

We are given with:

D=6cma=1.5m/s2d=1m

We have to find the cylinder’s angular speed in rpm.

02

Step 2. Calculation

The linear speed of string is:

v2=2adv=2×1.5×1v=1.73m/s

The angular speed is:

Ó¬=vrr=D/2r=0.06/2r=0.03mÓ¬=1.730.03Ó¬=57.74rad/s

To convert rad/s to rpm

role="math" localid="1647938262943" Ӭ=57.74×602πrpmӬ=550rpm

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