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A small child gives a plastic frog a big push at the bottom of a slippery 2.0-m-long, 1.0-m-high ramp, starting it with a speed of 5.0 m/s. What is the frog鈥檚 speed as it flies off the top of the ramp?

Short Answer

Expert verified

The speed of the frog at the top of the ramp is 2.2 m/sec

Step by step solution

01

Step 1. The slant distance of the ramp is S= 2m

The height of the ramp is H=1m
The speed of the frog is u=5m/sec

02

Step 2. To determine the final speed of the frog

The acceleration of the frog is given by a=gsin
Here, localid="1648212517867" sin=Height(H)Slantheight(S)

Substitute the values of slant height (S) and height (H)
sin=12

The acceleration due to gravity is g=10m/s2
Thus, the acceleration of the frog is localid="1648212652084" a=10(12)=5m/s2


Now, write the equation of motion,

v2-u2=2aS
substitute the known values,

v2-52=2(-5)(2)v2-25=-20v2=5v=5m/sec
Thus, the speed of the frog at the top of the ramp is 2.2 m/sec

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