91影视

We need to find the object鈥檚 speed and direction after the force ends.

For a short time a object receives a force is known as impulse. it is the area under the curve of the force-versus-time graph and it is the same as momentum. The impulse is the quantity $J_x$and it is given by equation in the form

$$\begin{gathered} impulse=J_x={鈭�}_{t_i}^{t_f}{F}_x\left(t\right)dt \\ =areaunderthe{F}_x\left(t\right)curvebetween{t}_{i}and{t}_f\left(1\right) \end{gathered}$$

In a graph of force versus time the force is in the range of time $鈻�t=1.0s$. the impulse takes the rectangle shape, where length is $l=1.0s$and width is $w=-2N$. The area of the rectangle is the product of the width and the length

$A=\left(width\right)\left(lenght\right)$

Using equation $\left(1\right)$to get impulse

$$\begin{gathered} J_x=\left(width\right)\left(length\right) \\ =(-2N)\left(1s\right) \\ =(-2kg)脳(m/s) \end{gathered}$$

The object has mass $m$and moves with speed $v$that has momentum $p$, Vector is a product of object's mass and its velocity.The momentum is given by equation in the form

$p=mv\left(2\right)$

Initial velocity $v_I=1.0m/s.$To get initial momentum $p_{ix}$of the object using equation $\left(2\right)$and putting values for $2kgand1.0m/s$.

$$\begin{gathered} p_{iv}=m{v}_i \\ =(2kg)(1.0m/s) \\ =(2kg)脳(m/s) \end{gathered}$$

The impulse changes its momentum to and it is given by equation in the form

$p_{fx}=p_{ix}+jx\left(3\right)$

Putting values forv$p_{ix}and{j}_x$in equation $\left(3\right)$to get $p_{fx}$

$$\begin{gathered} p_{fx}=p_{ix}+鈥�j_x \\ =(2kg)脳(m/s)+(-2kg)脳(m/s) \\ =(0kg)脳(m/s) \end{gathered}$$

Zero is the final momentum means objective has been stopped, and final velocity is zero

$v_f=0m/s$.