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FIGURE EX11.7 is an incomplete momentum bar chart for a 50 g particle that experiences an impulse lasting 10ms. What were the speed and direction of the particle before the impulse?

Short Answer

Expert verified

Speed is80m/sand direction is left.

Step by step solution

01

Given Information

We have given a momentum bar chart for a 50 g particle that experiences an impulse lasting 10ms.

02

Simplify

From the impulse-momentum theorem,

Pfx=Pix+Jx

From the momentum bar chart Pfx=-2kgm/sand Jx=6kgm/s, so we have

Pix=Pfx-Jx=-4kgm/s.

We have the mass of the particle is 50 g .

Pix=mvix

⇒vix=-4kgm/s0.05kg=-80m/s,

The particle is moving left since the sign is negative.

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