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Chapter 11: Q. 67 (page 290)

A proton (mass 1 u) is shot toward an unknown target nucleus at a speed of 2.50脳106 m/s. The proton rebounds with its speed reduced by 25% while the target nucleus acquires a speed of 3.12脳105 m/s. What is the mass, in atomic mass units, of the target nucleus?

Short Answer

Expert verified

Mass of the target nucleus is 14.02u

Step by step solution

01

Step 1. Given information is :Mass of the proton = 1uSpeed of the proton = 2.50×106m/sSpeed acquired by Target Nucleus = 3.12×105m/s

We need to find out the mass of the target nucleus in atomic mass units.

02

Step 2. Applying Law of conservation of Momentum

As the Proton rebounds with some speed, We can assume the collision to be elastic.

Using Law of conservation of Momentum,

mpvpi+mnvni=mpvpf+mnvnfu.2.5脳106m/s+0=(u)(-0.75脳2.5脳106m/s)+mn(3.12脳105m/s)mn=1.75脳2.5脳106m/s3.12脳105m/sumn=14.02u

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