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Chapter 11: Q. 60 (page 290)

Force F(x)=(10N)sin2蟺t4sis exerted on a 250 g particle during the interval0s鈮�t鈮�2.0s. If the particle starts from rest, what is its speed at t = 2.0 s?

Short Answer

Expert verified

The speed att=2.0secis50.92m/s

Step by step solution

01

Step 1. Given information

Force expression, F(x)=(10N)sin2蟺t4s

The time variation of force value.

02

Step 2. Apply and calculate

We apply the impulse-momentum theorem,

鈭�0210Nsin2蟺t4=0.25脳vfinal鈭�42蟺cos蟺鈭�cos0脳10=0.25脳vfinalvfinal=50.92m/s

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