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An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavier fragment slides 8.2m before stopping. How far does the lighter fragment slide? Assume that both fragments have the same coefficient of kinetic friction

Short Answer

Expert verified

The distance traveled by the lighter fragment side is400m

Step by step solution

01

Step 1. Given information

One fragment is seven times as massive as the other fragment.

The distance traveled by heavier fragment,8.2m

02

Step 2. Evaluating the velocities

Use the Newton's second law of motion,

Fheavier=aheaviermheavier=kgFlighter=alightermlighter=kg

Now, evaluating the velocities,

For heavier:

vheavier2=2dheaviervheavier=2kgmheavierdheavier

For lighter:

vlighter2=2alighterdlightervlighter=2kgmlighterdlighter

vlighter2vheavier2=dlighterdheavierdlighterdheavier=49dlighter=49dheavier

03

Step 3. Applying conservation principle

On applying conservation of momentum we have,

0=mheaviervheaviermlightervlightermheavier2kgmheavierdheavier-mheavier2kgmheavierdlighter=0dlighter=498.2400m

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