91影视

Mass of clay ball 1,$m_{Clayball1}=20g$

Mass of clay ball 2,$m_{clayball2}=30g$

The velocity of clay ball 1,$v_1=3m/s$

The velocity of clay ball 2,$v_2=2m/s$

To evaluate speed of clay ball 3.

Clay 1 travels east (in positive x-direction), while clay 2 travels north (in a negative x direction) (positive y direction) clay no. 2 The velocity of the ensuing ball of clay (which we'll call clay 3), is represented as

$v_3=v_3\cos 胃路\stackrel{鈫�}{i}+v_3\sin 胃路\stackrel{鈫�}{j}$

As we all know, each element's momentum is conserved individually.

For $x-$component,

$$\begin{gathered} {\left(p_1\right)}_x+{\left(p_2\right)}_x={\left(p_3\right)}_x \\ 0.02kg脳3m/s+0=0.05kg路v_3\cos 胃 \end{gathered}$$

$\begin{array}{r}0.02kg路3m/s+0=0.05kg路v_3\cos 胃\\ 鈬�v_3\cos 胃=1.2m/s\end{array}$

For y-component,

$\begin{array}{r}{\left(p_1\right)}_y+{\left(p_2\right)}_y={\left(p_3\right)}_y\\ 0+0.03kg.2m/s=0.05kg路v_3\sin 胃\\ 鈬�v_3\sin 胃=1.2m/s\end{array}$

From both the components,

$$\begin{gathered} \tan 胃=1 \\ 胃={45}^o \end{gathered}$$

Now evaluating the velocity,

$v_3\frac{\sqrt{2}}{2}=1.2鈬�v_3=1.7m/s$