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FIGURE P24.48shows two very large slabs of metal that are parallel and distance lapart. The top and bottom of each slab has surface area A. The thickness of each slab is so small in comparison to its lateral dimensions that the surface area around the sides is negligible. Metal 1has total charge Q1=Qand metal 2has total charge Q2=2Q. Assume Qis positive. In terms of Qand A, determine

a. The electric field strengths E1toE5in regions 1to 5.

b. The surface charge densities ηuto ηdon the four surfaces a to d.

Short Answer

Expert verified

(part a) The electric field strengths E1to E5in regions 1to 5.

a)

E1=3Q2Aϵ0E2=0E3=Q2Aϵ0E4=0E5=3Q2Aϵ0

(part b) The surface charge densities ηuto ηdon the four surface a to d.

b)

ηa=+3Q2Aηb=-Q2Aηc=+Q2Aηd=+3Q2A

Step by step solution

01

Step 1:

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Most popular questions from this chapter

What is the electric flux through each of the surfaces in FIGURE Q24.5? Give each answer as a multiple of qε0.

The two spheres in FIGURE Q24.8 on the next page surround equal charges. Three students are discussing the situation.

Student 1: The fluxes through spheres A and B are equal because they enclose equal charges.

Student 2: But the electric field on sphere B is weaker than the electric field on sphere A. The flux depends on the electric field strength, so the flux through A is larger than the flux through B.

Student 3: I thought we learned that flux was about surface area. Sphere B is larger than sphere A, so I think the flux through B is larger than the flux through A.

Which of these students, if any, do you agree with? Explain.

Suppose you have the uniformly charged cube in FIGURE Q24.1. Can you use symmetry alone to deduce the shape of the cube’s electric field? If so, sketch and describe the field shape. If not, why not?

A positive point chargeq sits at the center of a hollow spherical shell. The shell, with radius R and negligible thickness, has net charge -2q. Find an expression for the electric field strength (a) inside the sphere, r<K, and (b) outside the sphere, r>K. In what direction does the electric field point in each case?

FIGUREEX24.18shows three charges. Draw these charges on your paper four times. Then draw two-dimensional cross sections of three-dimensional closed surfaces through which the electric flux is (a) -q/ϵ0, (b) q/ϵ0, (c) 3q/ϵ0, and (d) 4q/ϵ0.

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