/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 44 A 2.0 m long, 1 mm diameter ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 2.0mlong, 1mmdiameter wire has a variable resistivity given by

localid="1649324855366" ÒÏ(x)=2.5×10-61+x1.02Ωm

where x is measured from one end of the wire. What is the current if this wire is connected to the terminals of a 9.0Vbattery?

Short Answer

Expert verified

The current in the wire will be0.6A.

Step by step solution

01

Given information

We have given

Length of the wire = 2m

Diameter of the wire = 1mm

Resistivity ÒÏ(x)=2.5×10-61+x1.02Ωm

Voltage = 9V

We have to find the current in the wire.

02

Simplify

We know the resistance

R=ÒÏLA

where area will be

A=πD24=π10-64=7.85×10-7m2

We can see here the length is 2m.

So x can change from 0to2.

Then

localid="1649325644831" R=1A∫02ÒÏ(x)dxR=17.85×10-7∫022.5×10-61+x1.02dxR=0.318x+x3302R=15Ω

Then current will be

I=VR=915I=0.6A

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.