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Chapter 28: Q. 35 (page 792)

A 10渭Fcapacitor initially charged to 20渭Cis discharged through a 1.0k惟 resistor. How long does it take to reduce the capacitor鈥檚 charge to 10渭C?

Short Answer

Expert verified

t=6.9ms time will be taken to reduce the cpacitor's charge to10渭C.

Step by step solution

01

Given Information  

We need to find that how long does it take to reduce the capacitor鈥檚 charge to 10渭C.

02

Simplify

The switch is off, the capacitor discharge and the current flows through the resistor. To discharge the capacitor, the charges flow through the circuit in time r. The initial charge Qois related to the final charge Qby equation in the form

Q=Qoe-tRC (1)

Here, Ris the resistance and Cis the capacitance. Let us solve equation (1) to get it by

t=-RCInQQo (2)

Now, putting the values forR,C,Qand Qointo equation (2) to get t

t=-RCInQQo=-(1000)(10脳10-6F)In10渭C20渭C=6.9脳10-3s=6.9ms

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Most popular questions from this chapter

a. What are the magnitude and direction of the current in the 18惟resistor in FIGURE EX28.5?

b. Draw a graph of the potential as a function of the distance traveled through the circuit, traveling cw from V=0Vat the lower left corner.

The tip of a flashlight bulb is touching the top of the 3Vbattery in FIGURE Q28.2. Does the bulb light? Why or why not?

The capacitor in an RC circuit is discharged with a time constant of 10ms. At what time after the discharge begins are

(a) the charge on the capacitor reduced to half its initial value and

(b) the energy stored in the capacitor reduced to half its initial value?

The circuit in FIGURE EX28.18is called a voltage divider. What value of Rwill make Vout=Vin/10?

What is the equivalent resistance between points a and b in FIGURE P28.45?
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