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Bulbs A and B in FIGURE Q28.11 are identical, and both are glowing. Bulb B is removed from its socket. Does the potential difference ∆V12between points 1 and 2 increase, stay the same, decrease, or become zero? Explain.

Short Answer

Expert verified

The potential difference is∆V12=0

Step by step solution

01

Given information and formula used 

Given :

Theory used:

The potential difference is equal to the amount of current multiplied by the resistance. A potential difference of one Volt is equal to one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.

02

Determining if the potential difference between points 1 and 2 increase, stay the same, decrease, or become zero 

Initially, the current flows between the two lights due to the battery's emf. Across bulb B, the voltage is greater than zero. When a bulb is removed from its socket, it takes on the appearance of a wire.

As a result, there is no possible difference between 1 and 2. That is,

∆V12=0

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