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A 2.0cm×2.0cmsquare loop of wire with resistance0.010Ωhas one edge parallel to a long straight wire. The near edge of the loop is cm from the wire. The current in the wire is increasing at the rate of 100A/s. What is the current in the loop?

Short Answer

Expert verified

The current in loop,Iinduced=44.2μA

Step by step solution

01

Introduction of loop

A loop is an electromagnetic system that uses two wires to send signals to a device. It can be used to produce energy or transmit data.

02

Simplify by values

Given values:

A=2.0cm×2.0cm

R=0.010Ω(ohm )

d=1.0cm

Magnetic flux of wire at distance :

B=μoI2πx

For a small strip of width dxflux:

dϕ=dAB=μoI2πx(0.02dx)

ϕ=∫0.010.03μoI2πxdx=μoI2πln3(0.02)

03

Find the worth of induce current

ε=dϕdt·Iinduced=εR
⇒Iinduced=μo2πRln3dIdt×(0.02)

localid="1650218054027">⇒Iinduced=4π×10×(1.098)m2π×0.1Ω×100×(0.02)

⇒Iinduced=44.2μA

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Most popular questions from this chapter

FIGURE EX30.8 shows a 2.0−cm−diameter solenoid passing through the center of a 6.0−cm−diameter loop. The magnetic field inside the solenoid is 0.20T. What is the magnetic flux through the loop when it is perpendicular to the solenoid and when it is tilted at a role="math" localid="1648914344990" 60∘angle?

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56. II Your camping buddy has an idea for a light to go inside your CALC tent. He happens to have a powerful (and heavy!) horseshoe magnet that he bought at a surplus store. This magnet creates a0.20T field between two pole tips 10cmapart. His idea is to build the hand-cranked generator shown in FIGURE P30.56. He thinks you can make enough current to fully light a1.0Ωlightbulb rated at 4.0W. That's not super bright, but it should be plenty of light for routine activities in the tent.

a. Find an expression for the induced current as a function of time if you turn the crank at frequency f Assume that the semicircle is at its highest point at t=0s.

b. With what frequency will you have to turn the crank tor the maximum current to fully light the bulb? Is this feasible?

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