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The force on the -1.0nCcharge is as shown inFIGURE CP22.76.What is the magnitude of this force?

Short Answer

Expert verified

The strength of the electric field is1.4410-3N/Cin the direction of the electron.

Step by step solution

01

Given information

The distance of the field point from the electron is1.0mm.

02

Explanation

In the present case,. the source charge is qelectron.

role="math" localid="1648483904923" E=140qr2r^1q=-1.610-19Cr=110-3mE=91091.610-1910-32directionistowardstheelectronE=1.4410-3N/Ctowardstheelectron

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Most popular questions from this chapter

Space explorers discover an 8.71017kgasteroid that happens to have a positive charge of 4400C. They would like to place their 3.3105kgspaceship in orbit around the asteroid. Interestingly, the solar wind has given their spaceship a charge of 1.2C. What speed must their spaceship have to achieve a 7500-km-diameter circular orbit?

A glass rod that has been charged to +12 nC touches a metal sphere. Afterward, the rod鈥檚 charge is +8.0 nC.

a. What kind of charged particle was transferred between the rod and the sphere, and in which direction? That is, did it move from the rod to the sphere or from the sphere to the rod?

b. How many charged particles were transferred?

FIGURE P22.51shows four charges at the corners of a square of side L. What is the magnitude of the net force onq?

You sometimes create a spark when you touch a doorknob after shuffling your feet on a carpet. Why? The air always has a few free electrons that have been kicked out of atoms by cosmic rays. If an electric field is present, a free electron is accelerated until it collides with an air molecule. Most such collisions are elastic, so the electron collides, accelerates, collides, accelerates, and so on, gradually gaining speed. But if the electron鈥檚 kinetic energy just before a collision is 2.010-18Jor more, it has sufficient energy to kick an electron out of the molecule it hits. Where there was one free electron, now there are two! Each of these can then accelerate, hit a molecule, and kick out another electron. Then there will be four free electrons. In other words, as FIGURE P22.61 shows, a sufficiently strong electric field causes a 鈥渃hain reaction鈥 of electron production. This is called a breakdown of the air. The current of moving electrons is what gives you the shock, and a spark is generated when the electrons recombine with the positive ions and give off excess energy as a burst of light.

  1. The average distance between ionizing collisions is 2.0m. (The electron鈥檚 mean free path is less than this, but most collisions are elastic collisions in which the electron bounces with no loss of energy.) What acceleration must an electron have to gain of kinetic energy in this distance?
  2. What force must act on an electron to give it the acceleration found in part a?
  3. What strength electric field will exert this much force on an electron? This is the breakdown field strength. Note: The measured breakdown field strength is a little less than your calculated value because our model of the process is a bit too simple. Even so, your calculated value is close.
  4. Suppose a free electron in air is 1.0 cm away from a point charge. What minimum charge is needed to cause a breakdown and create a spark as the electron moves toward the point charge?

Four lightweight balls A,B,C,andDare suspended by threads. Ball Ahas been touched by a plastic rod that was rubbed with wool. When the balls are brought close together, without touching, the following observations are made:

鈥 Balls B,C,andDare attracted to ball A.

鈥 Balls BandDhave no effect on each other.

鈥 Ball Bis attracted to ball C.

What are the charge states (glass, plastic, or neutral) of balls A,B,C,andD? Explain.

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