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Chapter 22: 28 - Excercises And Problems (page 625)

What are the strength and direction of the electric field 4.0 cm from a small plastic bead that has been charged to -8.0 nC?

Short Answer

Expert verified

The strength of the electric field is-4.5脳104N/C

Step by step solution

01

Given information

electron distance d=4.0脳10-2m

the charge of an electron is given by=-8脳10-9C

02

Explanation 

The electric fieldis defined as the electric force per unit charge.

E鈫�=F鈥�鈫�q

We want to find the electric field at a distance d=4.0脳10-2m. The electric field of a single point charge is given by E=keQd2

whereke=8.99脳109Nm2C鈭�2

So, substituting, we find the electric field at the distance d:

E=8.99脳109Nm2C鈭�2鈭�8.0鈰�10鈭�9C(0.04m)2=鈭�4.5脳104N/C

Therefore, the strength of the electric field is-4.5脳104N/C

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