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Chapter 8: Q.33 (page 200)

Space scientists have a large test chamber from which all the air can be evacuated and in which they can create a horizontal uniform electric field. The electric field exerts a constant horizontal force on a charged object. A 15gcharged projectile is launched with a speed of 6.0m/s at an angle35掳 above the horizontal. It lands 2.9m in front of the launcher. What is the magnitude of the electric force on the projectile?

Short Answer

Expert verified

The magnitude of the electric force on the projectile is0.034N.

Step by step solution

01

Given Infromation

Mass of charged particle m=15g=0.015Kg

Initial velocityvo=6m/s

Range R=2.9m.

02

Calculate the time of flight 

The time of the flight is:

t=2vosin胃g

Where,

v0is the initial velocity

gis the gravity acceleration

=2脳6脳sin35掳9.8

=0.702s

03

Using the equation of motion along horizontal direction,

Using the equation of motion along horizontal direction,

For horizontal direction:

x=vocos胃t+12axt2

localid="1648352197487" 2.9=6脳cos35掳脳0.70234+12ax脳0.702342

(2.9-4.915脳0.70234)脳2(0.70234)2=a

localid="1648352223322" a=2.238m/s2

localid="1648352255252" F=ma

Magnitude=15脳10-3脳2.238

F=0.034N

04

Final Answer

The magnitude of the electric force on the projectile is0.034N.

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