91影视

Student's arm length$=65cm$

The distance from the handle to the bottom of the bucket$=35cm$

Angular velocity can be characterized as the pace of progress of angular dislodging.

Calculate the minimum angular velocity of the bucket of the water. The total distance from the shoulder to the bucket is,

$R=65\mathrm{cm}+35\mathrm{cm}$

localid="1649398245082" $=\left(100\mathrm{cm}\left(\frac{{10}^{-2}\mathrm{m}}{1\mathrm{cm}}\right)\right)$

$=1\mathrm{m}$

The net force on the bucket of water is,

$F_{\text{net}}=F_{\text{cent}}$

Here,$F_{cent}$ is the centripetal force.
$mg=m{蝇}^{2}R$

$g={蝇}^{2}R$

Rearrange the above equation for$蝇$.

Rearrange the equation for $蝇$.

$蝇=\sqrt{\frac{g}{R}}$

Substitute the values

localid="1649398261321" $g=9.81\mathrm{m}/{\mathrm{s}}^2$

localid="1649398276295" $R=1\mathrm{m}$

localid="1649398291087" $蝇=\sqrt{\left(\frac{\left(9.81\mathrm{m}/{\mathrm{s}}^2\right)}{1\mathrm{m}}\right)}$

localid="1649398301907" $=\left(3.13\mathrm{rad}/\mathrm{s}\left(\frac{1\mathrm{rev}}{2蟺}\right)\right)$

$=29.9\mathrm{rpm}$

$鈮�30rpm$

The minimum angular velocity of the bucket of water is $29.9rpm$or$30\mathrm{rpm}$.