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Chapter 6: Q. 52 (page 156)

It鈥檚 a snowy day and you鈥檙e pulling a friend along a level road on a sled. You鈥檝e both been taking physics, so she asks what you think the coefficient of friction between the sled and the snow is. You鈥檝e been walking at a steady 1.5m/s, and the rope pulls up on the sled at a 30掳angle. You estimate that the mass of the sled, with your friend on it, is 60kg and that you鈥檙e pulling with a force of 75N. What answer will you give?

Short Answer

Expert verified

The co-efficient of friction is 渭=0.118

Step by step solution

01

Step 1. Given Information

We have,

walking at a steady v=1.5m/s

the rope pulls up on the sled at a 胃=30掳angle

and with your friend on it, is m=60kg and that you're pulling a force of T=75N

02

Step 2. Find the friction

the free body diagram, as shown above, with the pulling tension force of the rope Tacting at a 胃=30掳angle with the horizontal on the sled, the friction Ff, weigh FGand normal reactionn

Tsin胃+n-mg=0鈬�n=mg-Tsin胃Tcos胃-Ff=0鈬�Ff=渭n=渭(mg-Tsin胃)=Tcos胃

we can express the coefficient of friction as

渭=Tcos胃(mg-Tsin胃)渭=75cos(30)(60脳9.8-75sin(30))渭=0.118

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