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Chapter 27: Q. 3 (page 762)

1.0脳1016electrons flow through a cross section of a silver wire in 320渭s with a drift speed of 8.0脳10-4m/s. What is the diameter of the wire?

Short Answer

Expert verified

The diameter of the wire is0.93mm.

Step by step solution

01

Given Information

Number of electrons=1.0脳1016

Time=320渭s

Drift speed=8.0脳10-4m/s

02

Explanation

The electron density is

ie:=Nt

The current density is known to be

ie=neAvd.

The area of a circle is,

A=蟺D24鈬�D=4A蟺.

Write the area as

A=ienevd

Write the electron current and substitute,

A=Nnetvd

Now, substituting this expression for the area at the one for the diameter,

D=4N蟺netvd.

After substituting the values,

localid="1649322696741" D=4脳1脳1016e蟺脳5.8脳1028e脳3.2脳10-4渭s脳8脳10-4m/s

localid="1649322704585" =9.26脳10-4m.

03

Final Answer

Hence, the diameter of the wire is9.26脳10-4m.

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