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1.0×1020electrons flow through a cross-section of a 2.0mmdiameter iron wire in 5.0s. What is the electron drift speed?

Short Answer

Expert verified

The electron drift speed is75μm/s.

Step by step solution

01

Given Information 

Number of electrons flow through=1.0×1020

Diameter=2.0mm

Time=5.0s

02

Explanation 

The definition of the electron current includes the electron drift speed, which can be expressed as:

ie=neAvd⇒vd=ieneA

The electron current is just the number of electrons per unit time,

ie=Net

The area of the cross-section, since the latter is a circle, will be

A=Ï€D24

Combining, we can find

vd=Ne/tneπD2/4=4NeπnetD2

Substitute the values,

role="math" localid="1648798324977" vd=4×1020eπ·8.5·1028e×5s×0.002mm2

=7.5·10-5m/s.

03

Final Answer 

Hence, the electron drift speed is75μm/s.

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