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A hydrogen atom has orbital angular momentum 3.65×10-34Js

a. What letter s,p,dorf describes the electron?

b. What is the atom’s minimum possible energy? Explain.

Short Answer

Expert verified

a. The electron is L=3.

b. The atom’s minimum possible energy is-0.850eV

Step by step solution

01

Part (a) step 1: Given Information 

We need to describe the electron letter is s,p,dorf.

We have given angular momentum is3.65×10-34Js.

02

Part (a) step 2: Simplify

Finding orbital angular momentum is:

L=ll+1ħ

Lħ=ll+1ħħ (Divide both sides by h) Lħ=ll+1Lħ2=(ll+1)2Lħ2=ll+1

3.65×10-34Js1.5×10-34Js2=ll+112.08=ll+1⇒l=3

03

Part (b) step 1: Given Information 

We need to find the atom’s minimum possible energy.

04

Part (a) step 2: Simplify

Finding the atom minimum energy is :

Emin=-13.60eVn2wheren=4Emin=-13.60eV42Emin=-13.60eV16Emin=-0.850eV

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