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Chapter 32: Q. 8 (page 924)

A 0.30渭Fcapacitor is connected across an AC generator that produces a peak voltage of 10V. What is the peak current to and from the capacitor if the emf frequency is

(a) 100Hz?

(b)100kHz?

Short Answer

Expert verified

(a)Io=1.9脳10-3A

role="math" localid="1649956592903" (b)鈥�Io=1.9A

Step by step solution

01

Part (a) Step 1: Given Information:

We have been given that

Capacitance (C)= 0.30渭F

Peak voltage (Eo)= 10V

Emf frequency (n)= localid="1649958487243" 100Hz

02

Part (a) Step 2: Solving:

Peak current Iois given by :Io=Eo脳蝇脳C

Putting the value of(蝇)as2蟺nin the above equation:Io=Eo脳2蟺n脳C

Using the given values in the updated equation we get:Io=(10)脳2蟺(100)脳0.30脳10-6

There the peak value of current for a frequency of 100HzisIo=1.9脳10-3A

03

Part (b) Step 1: Given Information:

We have been given that

Capacitance (C)= 0.30uF

Peak voltage (Eo)= 10V

Emf frequency (n)=100kHz

04

Part (b) Step 2: Solving:

Using the expression of Io that we earlier used:Io=Eo脳2蟺n脳C

Putting the known values:Io=(10)脳2蟺100脳103脳0.30脳10-6

Io=1.9A

Therefore the peak current value for an emf frequency of100kHzis Io=1.9A

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Most popular questions from this chapter

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