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91Ó°ÊÓ

The emf phasor in FIGURE EX32 .1 is shown att=2.0ms.

a. What is the angular frequency Ó¬? Assume this is the first rotation.

b. What is the peak value of the emf?

Short Answer

Expert verified

The angular frequency Ó¬=1200rad/s and peak value of emf isE0=71V.

Step by step solution

01

Part (a) Step 1: Given information

We are given that

t=2ms∅=180∘-150∘=45∘

(as the phasor rotates anticlockwise towards X-axis)

02

Part (a) Step 2: Calculation

As we know that-

E=E0cos(Ӭt+∅)

Now converting 135 degree into radian

135∘=135∘×π°ù²¹»å180∘=3Ï€4

From here,

Ӭt=3π4Ӭ(2×10-3)=3π4Ӭ≈1200rad/s

03

Part (b) Step 1: Given information

We are given that

E=50Vwhen Ӭt=0and ∅=45∘.

04

Part (b) Step 2: Calculation

Now from the expression-

E=E0cos(Ӭt+∅)50V=E0cos(0+45∘)E0=50Vcos(45∘)E0=71V

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