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Chapter 32: Q. 1 (page 923)

The emf phasor in FIGURE EX32 .1 is shown att=2.0ms.

a. What is the angular frequency 蝇? Assume this is the first rotation.

b. What is the peak value of the emf?

Short Answer

Expert verified

The angular frequency 蝇=1200rad/s and peak value of emf isE0=71V.

Step by step solution

01

Part (a) Step 1: Given information

We are given that

t=2ms鈭�=180鈭�-150鈭�=45鈭�

(as the phasor rotates anticlockwise towards X-axis)

02

Part (a) Step 2: Calculation

As we know that-

E=E0cos(蝇t+鈭�)

Now converting 135 degree into radian

135鈭�=135鈭�脳蟺谤补诲180鈭�=3蟺4

From here,

蝇t=3蟺4蝇(2脳10-3)=3蟺4蝇鈮�1200rad/s

03

Part (b) Step 1: Given information

We are given that

E=50Vwhen 蝇t=0and 鈭�=45鈭�.

04

Part (b) Step 2: Calculation

Now from the expression-

E=E0cos(蝇t+鈭�)50V=E0cos(0+45鈭�)E0=50Vcos(45鈭�)E0=71V

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Most popular questions from this chapter

FIGURE EX32.24
shows voltage and current graphs for an inductor.

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