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The drawing shows two boxes resting on friction less ramps. One box is relatively light and sits on a steep ramp. The other box is heavier and rests on a ramp that is less steep. The boxes are released from rest at A and allowed to slide down the ramps. The two boxes have masses of 11 and 44 kg. If A and B are 4.5 and 1.5 m, respectively, above the ground, determine the speed of (a) the lighter box and (b) the heavier box when each reaches B. (c) What is the ratio of the kinetic energy of the heavier box to that of the lighter box at B?

Short Answer

Expert verified
(a) Speed of the lighter box: 9.39 m/s. (b) Speed of the heavier box: 5.42 m/s. (c) Ratio of kinetic energies: 1.35.

Step by step solution

01

Understand the Problem

We have two boxes sliding down frictionless ramps. One is light (11 kg) and sits on a 4.5 m high ramp, and the other is heavy (44 kg) on a 1.5 m high ramp. Both boxes start at rest and slide down. We need to find their speeds at the bottom and the ratio of their kinetic energies at the bottom of the ramps.
02

Apply Energy Conservation Principle

Since there is no friction and the boxes start at rest, we can use energy conservation. The potential energy at the top is converted into kinetic energy at the bottom for both boxes. The potential energy is given by: \[ PE = mgh \] where \( m \) is mass, \( g \) is acceleration due to gravity (9.8 m/s²), and \( h \) is height.
03

Calculate Final Speed of the Lighter Box

For the lighter box (mass = 11 kg, height = 4.5 m):1. Initial Potential Energy: \[ PE = mgh = 11 \times 9.8 \times 4.5 \]2. At the bottom, all potential energy is converted to kinetic energy: \[ KE = \frac{1}{2}mv^2 \]3. Set initial PE equal to final KE and solve for \( v \): \[ 11 \times 9.8 \times 4.5 = \frac{1}{2} \times 11 \times v^2 \]4. Cancel masses and solve:\[ v^2 = 2 \times 9.8 \times 4.5 \]\[ v = \sqrt{2 \times 9.8 \times 4.5} \]\[ v \approx 9.39 \, \text{m/s} \]
04

Calculate Final Speed of the Heavier Box

For the heavier box (mass = 44 kg, height = 1.5 m):1. Initial Potential Energy:\[ PE = mgh = 44 \times 9.8 \times 1.5 \]2. At the bottom, potential energy converts to kinetic energy:\[ KE = \frac{1}{2}mv^2 \]3. Set initial PE equal to final KE and solve for \( v \):\[ 44 \times 9.8 \times 1.5 = \frac{1}{2} \times 44 \times v^2 \]4. Cancel masses and solve:\[ v^2 = 2 \times 9.8 \times 1.5 \]\[ v = \sqrt{2 \times 9.8 \times 1.5} \]\[ v \approx 5.42 \, \text{m/s} \]
05

Calculate Kinetic Energy for Both Boxes

Calculate kinetic energy for both boxes at the bottom of the ramps using the formula:\[ KE = \frac{1}{2}mv^2 \]- Lighter Box:\[ KE_{11} = \frac{1}{2} \times 11 \times (9.39)^2 \approx 482.1 \text{ J} \]- Heavier Box:\[ KE_{44} = \frac{1}{2} \times 44 \times (5.42)^2 \approx 649.8 \text{ J} \]
06

Determine the Kinetic Energy Ratio

Calculate the ratio of the kinetic energy of the heavier box to the lighter box:\[ \text{Ratio} = \frac{649.8}{482.1} \approx 1.35 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a form of energy that an object possesses due to its motion. When an object moves, it gains energy from its velocity and mass. The kinetic energy (\( KE \)) of an object can be determined using the formula:
\[ KE = \frac{1}{2}mv^2 \]
where:
  • \( m \)is the mass of the object
  • \( v \)is the velocity of the object
In a scenario where a box slides down a frictionless ramp, the kinetic energy becomes crucial at the bottom of the ramp. This is because the potential energy, which the box initially has due to its height, is entirely transformed into kinetic energy as it moves downward. Understanding kinetic energy allows you to predict how fast an object will move at the bottom of a ramp when starting from rest at a certain height.
Potential Energy
Potential energy refers to the energy an object possesses because of its position or condition rather than its motion. In physics problems involving height, like those with ramps, gravitational potential energy is particularly relevant. It is calculated using:
\[ PE = mgh \]
where:
  • \( m \)is the mass of the object
  • \( g \)is the acceleration due to gravity (usually \( 9.8 \text{ m/s}^2 \) on Earth)
  • \( h \)is the height of the object above the ground
In the given exercise, the potential energy at the starting point depends on the mass and height of each box. As each box slides down the ramp without friction, this potential energy converts into kinetic energy, letting the box gain speed. Therefore, potential energy is crucial as the source of the speed that we calculate for the boxes at the bottom of the ramps.
Frictionless Ramp
A frictionless ramp is a theoretical construct where the surface offers no resistance to the movement of objects. This means that any object placed on a frictionless ramp will only be affected by gravity and will slide down without losing energy to friction. The assumption of a frictionless surface simplifies calculations, allowing us to use the conservation of energy principle without considering energy loss.
In scenarios with frictionless ramps, the potential energy from the height of an object entirely converts into kinetic energy as the object descends. This conversion is straightforward, as there is no energy dissipation due to friction. These conditions are ideal for illustrating the conservation of mechanical energy in physics problem-solving.
Physics Problem Solving
Solving physics problems, such as those involving energy conservation on ramps, requires a systematic approach. Here's how you can tackle these problems effectively:
  • **Understand the Problem:**Clearly identify the components involved in the scenario. Know your initial and final states, such as heights and masses.
  • **Apply the Conservation of Energy Principle:**Recognize that in a frictionless system, potential energy transforms into kinetic energy. Use \( mgh \) for potential energy and \( \frac{1}{2}mv^2 \) for kinetic energy.
  • **Simplify the Equations:**Since mass cancels out, focus on the height and velocity. Apply algebra to solve for the unknowns, typically final speed.
  • **Check Consistency:**Verify your results through units and logic to ensure reasonable outcomes.
Approaching the exercise in steps ensures clarity and reduces errors, helping you understand key physics concepts like energy conversion and motion dynamics.

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