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During a tug-of-war, team A pulls on team B by applying a force of 1100 N to the rope between them. The rope remains parallel to the ground. How much work does team A do if they pull team B toward them a distance of 2.0 m?

Short Answer

Expert verified
2200 Joules.

Step by step solution

01

Understand the Work Formula

The formula to calculate work (\(W\)) is given by \(W = F \times d \times \cos(\theta)\), where \(F\) is the force applied, \(d\) is the distance over which the force is applied, and \(\theta\) is the angle between the force and the direction of the motion. Since the rope remains parallel to the ground, \(\theta = 0^\circ\), hence \(\cos(0^\circ) = 1\).
02

Insert Values into the Formula

Substitute the given values into the formula: force \(F = 1100\,\text{N}\), distance \(d = 2.0\,\text{m}\), and \(\cos(0^\circ) = 1\). The formula becomes \(W = 1100\,\text{N} \times 2.0\,\text{m} \times 1\).
03

Calculate the Work

Perform the multiplication to find the work done: \(W = 1100 \times 2.0 = 2200\,\text{J}\). Thus, the work done is 2200 Joules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tug-of-War Physics
Tug-of-war is not just a fun game but a practical example of physics in action. When teams play tug-of-war, they apply force to a rope to pull the opposing team towards themselves. This force is directed along the rope, usually horizontally, and reflects Newton's Third Law: for every action, there is an equal and opposite reaction. This means if Team A pulls Team B with a certain force, Team B is exerting an equal force back, causing a balance unless the force applied by one is greater. In our example, Team A applies a force of 1100 N to the rope, which is significant enough to pull Team B over a distance. Understanding this concept allows us to analyze the forces at play in various scenarios and how they result in motion.
Force and Motion
Force and motion are two fundamental concepts of physics that explain how and why objects move. Force is any interaction that, when unopposed, changes the motion of an object. Forces can cause objects to start moving, stop moving, or change direction. Motion occurs when an object changes its position over time. In a tug-of-war scenario, the force exerted by Team A causes Team B to move towards them, covering a distance of 2.0 meters. Since the rope remains parallel to the ground, this means the force is applied horizontally. The absence of any angle in the force direction (other than 0 degrees) ensures that all the force contributes directly to the motion, making the scenario simpler to analyze. This direct relationship between force and motion is essential in calculating work.
Work Formula
Calculating work involves using the work formula, which considers multiple factors: force, distance, and the direction of the force relative to the distance moved. The work formula is given by:
  • \( W = F \times d \times \cos(\theta) \)
Where:
  • \( W \) is the work done in Joules,
  • \( F \) is the force applied in Newtons,
  • \( d \) is the distance covered in meters,
  • \( \theta \) is the angle between force and direction of motion.
In the tug-of-war example, the rope's horizontal alignment makes the angle \( \theta \) zero, simplifying our calculation because \( \cos(0^\circ) = 1 \). Thus, the formula simplifies to \( W = F \times d \). Plugging in the force of 1100 N and the distance of 2.0 meters results in work done as 2200 Joules. This straightforward equation emphasizes how closely linked force, motion, and energy are in physical activities.

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Most popular questions from this chapter

A semitrailer is coasting downhill along a mountain highway when its brakes fail. The driver pulls onto a runaway-truck ramp that is inclined at an angle of \(14.0^{\circ}\) above the horizontal. The semitrailer coasts to a stop after traveling 154 \(m\) along the ramp. What was the truck's initial speed? Neglect air resistance and friction.

A basketball of mass 0.60 kg is dropped from rest from a height of 1.05 m. It rebounds to a height of 0.57 m. (a) How much mechanical energy was lost during the collision with the floor? (b) A basketball player dribbles the ball from a height of 1.05 m by exerting a constant downward force on it for a distance of 0.080 m. In dribbling, the player compensates for the mechanical energy lost during each bounce. If the ball now returns to a height of 1.05 m, what is the magnitude of the force?

A bicyclist rides 5.0 km due east, while the resistive force from the air has a magnitude of 3.0 N and points due west. The rider then turns around and rides 5.0 km due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 3.0 N and points due east. (a) Find the work done by the resistive force during the round trip. (b) Based on your answer to part (a), is the resistive force a conservative force? Explain.

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Some gliders are launched from the ground by means of a winch, which rapidly reels in a towing cable attached to the glider. What average power must the winch supply in order to accelerate a 184-kg ultralight glider from rest to 26.0 m/s over a horizontal distance of 48.0 m? Assume that friction and air resistance are negligible, and that the tension in the winch cable is constant.

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