/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Bicyclists in the Tour de France... [FREE SOLUTION] | 91Ó°ÊÓ

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Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generated by seven-time-winner Lance Armstrong (m 75.0 kg) is 6.50 W per kilogram of his body mass. (a) How much work does he do during a 135-km race in which his average speed is 12.0 m/s? (b) Often, the work done is expressed in nutritional Calories rather than in joules. Express the work done in part (a) in terms of nutritional Calories, noting that 1 joule \(=2.389 \times 10^{-4}\) nutritional Calories.

Short Answer

Expert verified
(a) 5,484,375 J; (b) 1,309.46 Cal.

Step by step solution

01

Calculate Total Power

First, calculate the total power Lance Armstrong generates using his body mass. Given the power per kilogram is 6.50 W/kg, and his mass is 75.0 kg, the total power (P) is given by the formula: \(P = \text{power per kilogram} \times \text{mass}\). Substitute the values to find \(P\):\[P = 6.50\,\text{W/kg} \times 75.0\,\text{kg} = 487.5\,\text{W}\]
02

Find Race Duration

Next, calculate the time it takes to complete the 135-km race when traveling at an average speed of 12.0 m/s. Use the formula for time \(t = \text{distance} / \text{speed}\). Convert 135 km to meters first:\[135\,\text{km} = 135,000\,\text{m}\]Then calculate the time:\[t = \frac{135,000\,\text{m}}{12.0\,\text{m/s}} = 11,250\,\text{s}\]
03

Calculate the Work Done

Using the power calculated in Step 1 and the time from Step 2, calculate the total work done using the formula: \(W = P \times t\). Substitute the known values:\[W = 487.5\,\text{W} \times 11,250\,\text{s} = 5,484,375\,\text{J}\]
04

Convert Work to Nutritional Calories

Now, convert the work from joules to nutritional Calories using the given conversion factor: \(1\,\text{joule} = 2.389 \times 10^{-4}\,\text{nutritional Calories}\). Calculate the work in Calories:\[\text{Calories} = 5,484,375\,\text{J} \times 2.389 \times 10^{-4}\,\text{Cal/J} \approx 1,309.46\,\text{Cal}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work and Energy
In physics, the concept of work and energy is crucial for understanding how forces acting on an object result in motion. Work is defined as the product of the force applied to an object and the distance it moves in the direction of the force. It's denoted in joules (J). Energy, on the other hand, refers to the capacity to do work. There are different types of energy, including kinetic and potential energy, but in the context of cycling, we focus on mechanical energy.
Cyclists like Lance Armstrong convert biochemical energy from food into mechanical energy to pedal their bikes. The work done by a cyclist in a race measures how much energy is transferred from their body to propel the bicycle. This concept not only highlights human physical capacity but also relates to efficiency in endurance sports.
Power Calculation
Power is all about the rate at which work is done over time. It’s a measure of how quickly energy is being used. In simple words, it's how fast you can do work. Power is calculated using the formula \(P = \frac{W}{t}\), where \(W\) is the work done in joules and \(t\) is the time in seconds. Power is measured in watts (W).
In our example, Lance Armstrong generates a power of 6.50 W per kilogram of body mass. By using his total mass, we calculate the total power he produces during the race. Power is a crucial measure in cycling as it determines the cyclist's ability to maintain speed and overcome resistance like friction and air drag. The more power a cyclist has, the more effective and faster they can be.
Unit Conversion
Unit conversion is an essential skill in physics, especially when dealing with different measurement systems and requirements. Converting units involves changing a physical quantity from one unit to another without altering its value. This often requires multiplication or division by conversion factors.
In the exercise, we must convert kilometers to meters to calculate time, as speed was given in meters per second. Another critical conversion is transforming work done in joules to nutritional Calories to relate energy expenditure to dietary energy intake. Being proficient in unit conversion helps in understanding and solving real-world problems by using appropriate measurement systems effectively.
Nutritional Calories
Nutritional Calories, often simply referred to as Calories, are a measure of energy in food. One nutritional Calorie is equivalent to 1,000 scientific calories or one kilocalorie (kcal). In terms of physics, 1 joule is equivalent to \(2.389 \times 10^{-4}\) nutritional Calories.
In the context of the exercise, converting joules to nutritional Calories helps bridge the gap between physical energy exertion during the race and the dietary energy consumption a cyclist needs to sustain performance. This conversion is practical for athletes to plan their diet and energy intake effectively, especially during demanding events like the Tour de France.
Tour de France
The Tour de France is one of the most grueling and prestigious cycling events on the planet. It spans over 3,500 kilometers through varied terrains, challenging cyclists with multiple stages, including sprints and mountain climbs.
Cyclists like Lance Armstrong must maintain high levels of power to endure such a rigorous endurance event. Understanding the physics of cycling, such as work, power, and energy conversion, is vital to optimizing their performance. Properly managing energy through food intake, power output during races, and strategic energy conservation enables cyclists to perform at their best throughout the competition.

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