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A basketball player makes a jump shot. The 0.600-kg ball is released at a height of 2.00 m above the floor with a speed of 7.20 m/s. The ball goes through the net 3.10 m above the floor at a speed of 4.20 m/s. What is the work done on the ball by air resistance, a non conservative force?

Short Answer

Expert verified
The work done by air resistance is approximately -3.79 J.

Step by step solution

01

Define the Context

We need to find the work done by air resistance on the basketball as it moves from its initial position to the position where it passes through the net. The motion occurs in a straight line, experiencing two types of energy: kinetic and potential.
02

Apply the Work-Energy Principle

The work-energy principle states that the work done on an object is equal to the change in its kinetic energy plus the change in its potential energy. In this scenario, we can write: \( W = \Delta KE + \Delta PE \), where \( W \) is the work done by the air resistance, \( \Delta KE \) is the change in kinetic energy, and \( \Delta PE \) is the change in potential energy.
03

Calculate Initial and Final Kinetic Energies

The initial kinetic energy (\( KE_i \)) is calculated by the equation: \( KE_i = \frac{1}{2}mv_i^2 \). With \( m = 0.600 \, \text{kg} \) and \( v_i = 7.20 \, \text{m/s} \), we get \( KE_i = \frac{1}{2} \times 0.600 \times 7.20^2 = 15.552 \, \text{J} \). The final kinetic energy (\( KE_f \)) is \( KE_f = \frac{1}{2}mv_f^2 \), where \( v_f = 4.20 \, \text{m/s} \). Therefore, \( KE_f = \frac{1}{2} \times 0.600 \times 4.20^2 = 5.292 \, \text{J} \).
04

Calculate Initial and Final Potential Energies

The potential energy is given by \( PE = mgh \), where \( g = 9.81 \, \text{m/s}^2 \). The initial height is \( h_i = 2.00 \, \text{m} \), so \( PE_i = 0.600 \times 9.81 \times 2.00 = 11.772 \, \text{J} \). The final height is \( h_f = 3.10 \, \text{m} \), and \( PE_f = 0.600 \times 9.81 \times 3.10 = 18.246 \, \text{J} \).
05

Calculate Change in Energies

The change in kinetic energy is \( \Delta KE = KE_f - KE_i = 5.292 - 15.552 = -10.260 \, \text{J} \). The change in potential energy is \( \Delta PE = PE_f - PE_i = 18.246 - 11.772 = 6.474 \, \text{J} \).
06

Compute the Work Done by Air Resistance

Using the work-energy principle formula \( W = \Delta KE + \Delta PE \), substitute the change in energies: \( W = -10.260 + 6.474 = -3.786 \, \text{J} \). So, the work done by air resistance on the basketball is approximately \(-3.79 \, \text{J}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is the energy of motion. Whenever an object is moving, it possesses kinetic energy. The amount of kinetic energy depends on two key factors: the mass of the object and its velocity (speed with direction). The formula to calculate kinetic energy (\( KE \)) is: \( KE = \frac{1}{2} m v^2 \), where \( m \) is the mass and \( v \) is the velocity.
It's essential to understand that kinetic energy increases with the velocity squared. This means that if the speed of an object doubles, its kinetic energy quadruples. This principle helps us understand why faster moving objects have significantly more energy.
In our basketball example, the ball starts with a certain kinetic energy because it's moving at 7.20 m/s. As the ball goes through the net, its velocity decreases to 4.20 m/s, resulting in a decrease in kinetic energy. This change plays a crucial role in calculating the work done on the ball by the air resistance.
Potential Energy
Potential energy is stored energy that an object possesses due to its position or condition. For objects near the earth, gravitational potential energy is the most relevant. This type of potential energy is determined by the height of an object above the ground, the object's mass, and the gravitational acceleration (usually \( 9.81 \, \text{m/s}^2 \) on Earth). The formula for gravitational potential energy (\( PE \)) is: \( PE = mgh \), where \( m \) is the mass, \( g \) is the gravitational acceleration, and \( h \) is the height.
When considering our basketball scenario, the ball initially has potential energy based on its height of 2.00 m above the floor. As it rises to a new height of 3.10 m, its potential energy increases. This change in height means a change in potential energy, which contributes to the calculation of work done on the ball by non-conservative forces, like air resistance.
Non-Conservative Forces
Non-conservative forces include forces that cause energy to be dissipated from a system, such as friction or air resistance. These forces do not conserve mechanical energy, meaning they can change the total energy of a system in ways that cannot be recovered simply by retracing a path.
In our basketball problem, air resistance acts as a non-conservative force that does work on the ball as it moves through the air. Unlike conservative forces (like gravity) that only transfer energy between kinetic and potential forms, non-conservative forces reduce the system's mechanical energy, often converting it into heat or sound.
The work done by air resistance, calculated using the work-energy principle, shows how much energy was taken away from the system due to this non-conservative force. Here, the work done by air resistance is negative, indicating that the ball loses mechanical energy as it travels from its initial to final position.

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Most popular questions from this chapter

An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of \(4.5 \times 10^{4} kg\) , and the force causes its speed to change from 7100 to 5500 \(m/ s\) . ( a What is the work done by the force? (b) If the asteroid slows down over a distance of \(1.8 \times 10^{6} m,\) determine the magnitude of the force.

Under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. When the drive force is shut off, the snowmobile coasts to a halt. The snowmobile and its rider have a mass of 136 kg. Under the influence of a drive force of 205 N, it is moving at a constant velocity whose magnitude is 5.50 m/s. The drive force is then shut off. Find (a) the distance in which the snowmobile coasts to a halt and (b) the time required to do so.

A \(1200-\mathrm{kg}\) car is being driven up a \(5.0^{\circ}\) hill. The frictional force is directed opposite to the motion of the car and has a magnitude of \(f=524 \mathrm{N}\) . A force \(\overrightarrow{\mathbf{F}}\) is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight \(\overrightarrow{\mathbf{W}}\) and the normal force \(\overrightarrow{\mathbf{F}}_{\mathrm{N}}\) directed perpendicular to the road surface. The length of the road up the hill is 290 \(\mathrm{m}\) . What should be the magnitude of \(\overrightarrow{\mathbf{F}},\) so that the net work done by all the forces acting on the car is \(+150 \mathrm{kJ}\) ?

A semitrailer is coasting downhill along a mountain highway when its brakes fail. The driver pulls onto a runaway-truck ramp that is inclined at an angle of \(14.0^{\circ}\) above the horizontal. The semitrailer coasts to a stop after traveling 154 \(m\) along the ramp. What was the truck's initial speed? Neglect air resistance and friction.

A basketball of mass 0.60 kg is dropped from rest from a height of 1.05 m. It rebounds to a height of 0.57 m. (a) How much mechanical energy was lost during the collision with the floor? (b) A basketball player dribbles the ball from a height of 1.05 m by exerting a constant downward force on it for a distance of 0.080 m. In dribbling, the player compensates for the mechanical energy lost during each bounce. If the ball now returns to a height of 1.05 m, what is the magnitude of the force?

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