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Electromagnetic "waves" strike a single slit of1渭尘width. Determine the angular full width (angle from first minimum on one side of the center to first minimum on the other) in degrees of the central diffraction maximum if the waves are (a) visible light of wavelength 500 nmand (b) X-rays of wavelength 0.05 nm. (c) Which more clearly demonstrates a wave nature?

Short Answer

Expert verified

(a) The wave particle duality if visible light is there is 60.

(b) The wave particle duality if x-ray is there is 5.72x10-3.

(c) The visible light will more clearly demonstrate the wave nature

Step by step solution

01

Identification of the given data

The given data is listed as follows,

The width of the single slit is, a=1渭尘x1x10-6m1渭尘=1x10-6m

The wavelength of the visible light is, 1=500nm110-9m1nm=50010-9m

The wavelength of x-ray is, 2=0.05nm110-9m1nm=0.0510-9m

02

Representation of the single slit diffraction formula

The single slit diffraction formula is expressed as follows,

asin()=苍位

Here, a is the width of the single slit, is the wavelength of the light wave, n is the order of the minimum, and is the angle with the direction of the light.

03

(a) Determination of wave-particle duality if visible light is there

Rearrange the single slit diffraction formula.

=sin-1苍位a

Substitute all the values in the above expression.

=sin-1150010-9m110-6m=30

It is known that the angular full width is twice the above value. So, multiply the above value by 2.

=230=60

Thus, the wave particle duality if visible light is there is 60.

04

(b) Determination of wave-particle duality if x-ray is there

Rearrange the single slit diffraction formula.

=sin-1苍位a

Substitute all the values in the above expression.

=sin-110.0510-9m110-6m=2.8610-3

It is known that the angular full width is twice the above value. So, multiply the above value by 2.

=(28610-3)=5.7210-3

Thus, the wave particle duality if x-ray is there is 5.7210-3.

05

(c) Identification of the most clear wave nature

Generally, as the wavelength increases, the wave nature (diffraction) of the light dominates which is the case of visible light here. In addition, the results indicate that the particle nature will become significant as the wavelength of the incident particles is much less than the width of the slit which is the case for the -ray here.

Thus, the visible light will more clearly demonstrate the wave nature.

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