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Verify that equation (4-19) follows from (4-16) and (4-18).

Short Answer

Expert verified

The proof of the equation r=402me2n2 is stated below.

Step by step solution

01

Velocity in terms of charge and permittivity of free space.

According to Bohr model, the expression for the velocity of an electron, rotating around a proton, in terms of charge and permittivity of free space is given by,

v2=e24蟺蔚omr(1)

According to the Bohr model, only those orbits are available for the revolution of electrons, for which the angular momentum is an integral multiple of. Where,

and his Planck鈥檚 constant (h=6.62610-34kgm2s).

Thus, for an electron of mass m moving in an orbit of radius r and moving with velocity v, the angular momentum L is given as-

L=mvrL=nv=nmr(2)

02

Proof the equation r=4πε0ℏ2me2n2 with the help of equation (1)

Consider an electron, having charge e, rotating around a proton in a circular orbit of radius r, for which the electron of mass mhas angular momentumLand is moving with velocityv.

Using equations (1) and (2), the following relation can be obtained-

v2=e240mr

n22m2r2=e240mr

n22=mre240r=n2240me2

Therefore, the equation r=(40)2me2n2is proved.

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