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Chapter 10: Q65E (page 470)

Question: When electrons cross from the n-type to the p-type to equalize the Fermi energy on both sides in an unbiased diode they leave the n-type side with an excess of positive charge and give the p-type side an excess of negative. Charge layers oppose one another on either side of the depletion zone, producing. in essence, a capacitor which harbors the so-called built-in electric

field. The crossing of the electrons to equalize the Fermi energy produces the dogleg in the bands of roughly Egap , and the corresponding potential differerence

is Egap /e. The depletion zone in a typical diode is wide, and the band gap is 1.0 eV. How large is the built-in electric field?

Short Answer

Expert verified

Answer

The build in electric field is .

Step by step solution

01

Given data

Electric field is uniform.

02

Concept of electric field

Electric鈥�field=Potential differencewidth

03

Determine the built-in electric field

Determine the built-in electric field.

Electric field=Potential differencewidth=Egape脳width

Solve further as shown below.

Electric field=1.0eVe脳1渭m=1.0eVe脳10-6m=10-6v/m

The build in electric field is 10-6v/m.

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