/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q18P If an object’s rotational kine... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If an object’s rotational kinetic energy is 50 J and it rotates with an angular speed of 12 rad/s, what is the moment of inertia?

Short Answer

Expert verified

The moment of inertia is,0.69kg.m2 .

Step by step solution

01

Identification of the given data

The given data can be listed below as,

  • The kinetic energy of the object is,Krot=50J.
  • The angular speed of object is, Ó¬=12rad/s
02

Significance of rotational kinetic energy

The rotational kinetic energy of a rotating object can be expressed as half the product of the object's angular velocity and its moment of inertia about its axis of rotation.

03

Determination of the moment of inertia

The relation of rotational kinetic energy is expressed as,

Krot=12IÓ¬2 ...(i)

Here Krotis the rotational kinetic energy, Ó¬is the angular speed andIis the moment of inertia.

Substitute 50 J for Krot, and 12 rad/s for Ó¬in the equation (i).

role="math" localid="1657850631785" 50J=12×I×12rad/s2I=0.69kg.m2

Hence the moment of inertia is, 0.69kg.m2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Discuss qualitatively the motion of the atoms in a block of steel that falls onto another steel block. Why and how do large-scale vibrations damp out?

By calculating numerical quantities for a multiparticle system. One can get a concrete sense of the meaning of the relationships p→sys=Mtotv→CMand Ktot=Ktrans+Krel. Consider an object consisting of two balls connected by a spring, whose stiffness is 400 N/m. The object has been thrown through the air and is rotating and vibrating as it moves. At a particular instant, the spring is stretched 0.3m, and the two balls at the ends of the spring have the following masses and velocities: 1:5kg.(8,14,0)m/s2:3kg(-5,9,0)m/s

(a)For this system, calculate p→sys. (b) Calculate v→CM(c) Calculate Ktot3. (d) Calculate Ktrans. (e) Calculate Krel. (f) Here is a way to check your result for Krel. The velocity of a particle relative to the center of mass is calculated by subtracting v→CMfrom the particle’s velocity. To take a simple example, if you’re riding in a car that’s moving with v→CM,x=20m/sand you throw a ball with v→CM,x=35m/s, relative to the car, a bystander on the ground sees the ball moving with vx=55m/sSo v→=v→CM=v→reland therefore we have=v→relv→=v→CMfor each mass and calculate the correspondingKrel. Compare with the result you obtained in part (e).

A man whose mass is 80kg and a woman whose mass is 50kgsit at opposite ends of a canoe 5m long, whose mass is 30kg. (a) Relative to the man, where is the mass of the system consisting of man-woman, and canoe? (Hint: Choose a specific coordinate system with a specific origin.) (b) Suppose that the man moves quickly to the center of the canoe and sits down there. How far does the canoe move in the water? Explain your work and your assumptions.

A string is wrapped around a disk of mass 2.1 kg (its density is not necessarily uniform). Starting from rest, you pull the string with a constant force of 9 N along a nearly frictionless surface. At the instant when the center of the disk has moved a distance 0.11 m, your hand has moved a distance of 0.28 m (Figure 9.51).


(a) At this instant, what is the speed of the center of mass of the disk? (b) At this instant, how much rotational kinetic energy does the disk have relative to its center of mass? (c) At this instant, the angular speed of the disk is 75 rad/s. What is the moment of inertia of the disk?

Three uniform-density spheres are positioned as follows:

  • A3kg sphere is centered at <10,20,-5>m.
  • A 5kgsphere is centered at <4,-15,8>m.
  • A 6kgsphere is centered at <-7,10,9>m.

What is the location of the center of mass of this three-sphere system?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.