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The driver of a car traveling at a speed of 18 m/s slams on the brakes and comes to a stop in 4s . If we assume that the car's speed changed at a constant rate (constant net force): (a) what was the car's average speed during this 4 s interval? (b) How far did the car go in this 4 s interval?

Short Answer

Expert verified

(a) Average speedvavg=9 m/s

(b) Distance traveldt=36m

Step by step solution

01

Identification of given data

  • Initial velocity vi=18m/s
  • Final velocity vf=0
  • Time requiredt=4s
02

Average speed

Average speed is ratio of total distance travelled in a particular period of time.

03

Calculation for the average speed

(a) The average speed of an object is calculated by

vavg=dtt

Here,

dt = Total distance

t = Total time

If the speed changes at a constant rate, the average speed is the initial and final velocity arithmetic mean.

vavg=vi+vf2vavg=18+02vavg=9m/s

Then, The average speed will bevavg=9m/s

04

Calculation for the distance travel

(b) Use the equation refeered to in step 2

vavg=dttdt=vavg×tdt=9m/s×4sdt=36m

Hence the total distance traveldt=36m

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