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What is the energy of the photon emitted by the harmonic oscillator with stiffness ks and mass m when it drops from energy level 5 to energy level 2?

Short Answer

Expert verified

The energy emitted by the photon is 3ksm.

Step by step solution

01

Identification of given data

The mass of harmonic oscillator ism.

The stiffness of harmonic oscillator is ks.

The higher energy level for photon is nh=5.

The lower energy level for photon is nl=2.

02

Conceptual Explanation

The energy of the photon is always in quantized form and energy emitted by photon is equal to the drop in energy between these levels.

03

Determination of energy emitted by the photon

The angular frequency of the harmonic oscillator is given as:

0=ksm

The energy of harmonic oscillator for higher level is given as:

Eh=nh0

The energy of harmonic oscillator for lower level is given as:

El=nl0

The energy emitted by the photonis given as:

E=Eh-ElE=nh0-nl0E=nh-nlksm

Here, is the Planck鈥檚 constant.

Substitute all the values in the above equation.

E=5-2ksmE=3ksm

Therefore, the photon emits the energy 3ksm between given levels of harmonic oscillator.

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