91影视

The given data can be listed below as-.

The photon energies detected by the photon detector are$E_1=0.3eV,E_2=0.5eV,E_3=0.8eV,E_4=2.0eV,E_5=2.5eV,E_6=2.8eV$

The photon鈥檚 energy is equal to the product of the Planck鈥檚 constant and the frequency of the photon.

The expression for the energy of the photon is given as follows,

$E=hv$

Here, h is the Planck鈥檚 constant and v is the frequency.

The energy-level diagram of the microscopic objects is shown as follows,

During the energy exchange $E=hv$, the electrodes mainly move from one orbit to another. The absorption layers mainly consist of the ground state,${\mathrm{E}}_1=0.3\mathrm{eV},{\mathrm{E}}_3=0.8\mathrm{eV},\mathrm{and}{\mathrm{E}}_6=2.8\mathrm{eV}$ due to the passing of the light via material at a low temperature.

Thus, the absorption layers mainly consist of the ground state , ${\mathrm{E}}_1=0.3\mathrm{eV},{\mathrm{E}}_3=0.8\mathrm{eV},\mathrm{and}{\mathrm{E}}_6=2.8\mathrm{eV}$due to the passing of the light via the material at a low temperature.

The spring-mass system mainly works as a simple oscillator that has evenly spaced levels of energy and not suitable for the microscopic objects.

Thus, a spring-mass model may not be good for these microscopic objects.

From the energy-level diagram, it is evident that there are mainly three types of photon energyin the beam of light are reducingthat includes highest-energy, second highest energy, and the lowest energy dark. Hence, from the energy level diagram, the values are , ${\mathrm{E}}_6=2.8\mathrm{eV},{\mathrm{E}}_3=0.8\mathrm{eV},\mathrm{and}{\mathrm{E}}_1=0.3\mathrm{eV}$respectively.

Thus, the photon energies in this beam of light that are observed to be reduced significantly in intensity are ,${\mathrm{E}}_6=2.8\mathrm{eV},{\mathrm{E}}_3=0.8\mathrm{eV},\mathrm{and}{\mathrm{E}}_1=0.3\mathrm{eV}.$