91Ó°ÊÓ

The given data can be listed below,

1. The electric field ${\stackrel{→}{E}}_1$due to charge$-q_1$ .
2. The electric field ${\stackrel{→}{E}}_2$due to charge $+q_2$.

The term polarization, also known as electric polarization, is the alignment of the dipole moments of permanent or induced dipoles in the direction of an applied electric field.

The polarization of charges is shown below in the diagram.

Thus, in the diagram of the charges present, polarize the metal piece. The positive charge attracts the metal's free electrons, leaving an electron deficiency or, to put it another way, a positive charge attracting the negative charge.

The diagram for electric fields is given below,

Thus, the vector fields ${\stackrel{→}{E}}_1$were drawn, due to the $-q_1$charge, the vector field ${\stackrel{→}{E}}_2$due to the charge and the resulting vector field ${\stackrel{→}{E}}_3$.

Positive charge generates a force and, as a result, an electric field ${\stackrel{→}{E}}_2$in the opposite direction of the charge-point X line. The negative charge at point A attracts it with its electric field ${\stackrel{→}{E}}_1$, which is parallel to the force. The resulting field ${\stackrel{→}{E}}_1$is obtained by summing these two vectors.

Thus, the positive charges produce a force and hence an electric field ${\stackrel{→}{E}}_2$in the opposite direction of the charge-point X line. At point A, the negative charge causes an attractive force towards it, and its electric field ${\stackrel{→}{E}}_1$follows the force. The sum of these two vectors produces the final field${\stackrel{→}{E}}_3.$