/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q46P You drag a block across a table ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q46P (page 167)

You drag a block across a table while a friend presses down on the block. The coefficient of friction between the table and the block is 0.6. The vertical component of the force exerted by the table on the block is 190N. How big is the horizontal component of the force exerted by the table on the block?

Short Answer

Expert verified

The horizontal component of the force is 114N.

Step by step solution

01

Identification of the given data

The coefficient of friction between the table and the block is碌=0.6

The vertical component of the force exerted by the table on the block isN=190N

02

Determination of the horizontal component of the force exerted by the table on the block

Force,

F=渭N=0.6脳190=114N

Hence the horizontal component of the force exerted by the table on the block is 114N.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Young鈥檚 modulus for aluminium is .The density of aluminium is ,and the mass of one mole is 27g. If we model the interactions of neighbouring aluminium atoms as though they were connected by spring, determine the approximate spring constant of such a spring. Repeat this analysis for lead is: Young鈥檚 modulus for Lead and the density of lead is , and the mass of one mole is 207g. Make a note of these results, which we will use for various purposes later on. Note that aluminium is a rather stiff material, whereas lead is quite soft.

Bob is pushing a box across the floor at a constant speed of , applying a horizontal force whose magnitude is20N . Alice is pushing an identical box across the floor at a constant speed of 2m/s, applying a horizontal force. (a) What is the magnitude of the force that Alice is applying to the box? (b) With the two boxes starting from rest, explain qualitatively what Alice and Bob did to get their boxes moving at different constant speeds.

In a spring-mass oscillator, when is the magnitude of momentum of the mass largest: when the magnitude of the net force acting on the mass is largest, or when the magnitude of the net force acting on the mass is smallest?

A 15kgbox sits on a table. The coefficient of static friction localid="1657707248507" 渭sbetween table and box is 0.3, and the coefficient of kinetic friction 渭kis 0.2. (a) What is the force required to start the box moving? (b) What is the force required to keep it moving at constant speed? (c) What is the force required to maintain an acceleration of2m/s/s?

A hanging titanium wire with diameter2mm(2脳10-3m) is initially 3mlong. When a 5kgmass is hung from it, the wire stretches an amount 0.4035mm, and when a 10kgmass is hung from it, the wire stretches an amount 0.807mm. A mole of titanium has a mass of 48g, and its density is 4.51g/cm3. Find the approximate value of the effective spring stiffness of the interatomic force, and explain your analysis .
See all solutions

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

Read Explanation

Physics of Motion

Read Explanation

Modern Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Fundamentals of Physics

Read Explanation

Electromagnetism

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.