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You drag a block across a table while a friend presses down on the block. The coefficient of friction between the table and the block is 0.6. The vertical component of the force exerted by the table on the block is 190N. How big is the horizontal component of the force exerted by the table on the block?

Short Answer

Expert verified

The horizontal component of the force is 114N.

Step by step solution

01

Identification of the given data

The coefficient of friction between the table and the block isµ=0.6

The vertical component of the force exerted by the table on the block isN=190N

02

Determination of the horizontal component of the force exerted by the table on the block

Force,

F=μN=0.6×190=114N

Hence the horizontal component of the force exerted by the table on the block is 114N.

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