/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13Q In a spring-mass oscillator, whe... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q13Q (page 165)

In a spring-mass oscillator, when is the magnitude of momentum of the mass largest: when the magnitude of the net force acting on the mass is largest, or when the magnitude of the net force acting on the mass is smallest?

Short Answer

Expert verified

The magnitude of the momentum of mass is largest when the magnitude of the net force acting on the mass is largest.

Step by step solution

01

Spring-mass system

A spring-mass system is a spring system with a block hanging or connected at the free end. Any item executing a basic harmonic motion may generally be found using the spring-mass system.

02

Explanation

Expression for the spring-mass system

mx+kx=Fs

Where is the mass of an object, x is the displacement of an object, k is the stiffness of spring, and Fs is the force applied to the object.

As the above equation shows, as the momentum of mass is largest, then the net force acting on the mass is largest.

Thus, in a spring-mass oscillator, the magnitude of the momentum of mass is largest when the magnitude of the net force acting on the mass is largest.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For this problem you will need measurements of the position vs. time of a block sliding on a table, starting with some initial velocity, showing down, and coming to rest. If you do not have an appropriate laboratory setup for making these measurements, your instructor will provide you with such data. Analyze these data to determine the coefficient of friction and to see how well they support the assertion that the force of sliding friction is essentially independent of the speed of sliding.

: A hanging wire made of an alloy of iron with diameter 0.09cm is initially 2.2m long. When a 66kg mass is hung from it, the wire stretches an amount of 1.12cm. A mole of iron has a mass of 56g, and its density is 7.87 g/cm. Based on these experimental measurement, what is Young鈥檚 modulus for this alloy iron

The diameter of a copper atom is approximately2.28脳10-10m. The mass of one mole of copper is 64g. Assume that the atoms are arranged in a simple cubic array. Remember to convert to SI units. (a) What is the mass of one copper atom, in kg? (b) How many copper atoms are there in a cubical block of copper that is 4.6 cmon each side? (c) What is the mass of the cubical block of copper, in kg?

A bouncing ball is an example of an anharmonic oscillator. If you Quadruple the maximum height, what happens to the period? (Assume that the ball keeps returning to the same height.)

A 5kgbox with initial speed 4m/sslides across the floor and comes to a stop after 0.7s(a) what is the coefficient of kinetic friction? (b) How far does the box move? (c) You put a 3kgblock in the box, so the total mass is now 8kg, and you launch this heavier box with an initial speed of 4m/s. How long does it take to stop?
See all solutions

Recommended explanations on Physics Textbooks

Nuclear Physics

Read Explanation

Atoms and Radioactivity

Read Explanation

Solid State Physics

Read Explanation

Rotational Dynamics

Read Explanation

Space Physics

Read Explanation

Translational Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.