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Chapter 19: Q50P (page 799)

When a single thin-filament bulb is connected to a 1.5Vbattery, the current through the battery is about80mAIf you add another thin-filament bulb in parallel, the battery current of course increase to160mA. Is the battery ohmic? That is, is the current through the battery proportional to the potential difference across the battery?

Short Answer

Expert verified

No

Step by step solution

01

Given Data

VoltageV=1.5VCurrentI1=80mAI2=160mA

02

Concept

Generally, the current is proportional to the difference of electric potential. The current is inversely proportional to the resistance.

03

Find the battery is ohmic

  • The battery is not ohmic.
  • The current is not proportional to voltage.
  • If you double the current through a battery, the battery voltage hardly changes at all.
  • The battery voltage certainly does not double and will actually decrease slightly.
  • The battery voltage is not proportional to the current.

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Most popular questions from this chapter

Two resistor each with resistance of 4脳106惟 are connected in series to a 60 V power supply whose internal resistance is negligible. You connect the voltmeter across one of these resistors and this voltmeter has an internal resistance of 1脳106惟. What is the reading on the voltmeter?

State whether the following statement is true or false, and briefly explain why: 鈥淚n the two circuits shown in Figure 19.64, the battery output power is greater in circuit 2 because there is an additional resistor dissipating power.鈥�

In copper at room temperature, the mobility of mobile electrons is about 4.5脳10-3(m/s)V/m,and there are about8脳1028mobile electrons perm3Calculate the conductivity蟽and include the correct units. In actual practice, it is usually easier to measure the conductivity蟽and deduce the mobilityufrom this measurement.

The capacitor in Figure 19.65 is initially charged, then the circuit is connected. Which graph in Figure 19.66 best describes the current through the bulb as a function of time?

When a particular capacitor, which is initially uncharged, is connected to a battery and a small light bulb, the light bulb is initially bright but gradually gets dimmer, and after 45s it goes out. The diagrams in Figure 19.71 show the electric field in the circuit and the surface charge distribution on the wires at three different times ( 0.01s, 8s, and 240s) after the connection to the bulb is made. Which of the diagrams best represents the state of the circuit at each time specified?

(a)0.01safter the connection is made,

(b)8safter the connection is made,

(c)240safter the connection is made.
See all solutions

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